Hi, I'm currently working on understanding the x86 assembly language. I am currently stuck on understanding this instruction: mov 0x28e89c (%rip), %eax I know that rip is the instruction pointer that holds the address of the next instruction and that eax is the destination for whatever 0x28e89c (%rip) is. I assume that the 0x28e89c is an offset of some sort but I don't know how to interpret it. If anyone could help it would be much appreciated, thanks!
EIP is the instruction pointer not RIP... Maybe this is a typo... 0x28e89c is the offset to the address pointed by eip Eg :- if EIP points to 0xDEADBEEF The the instruction will point to :- Code: 0xDEADBEEF + 0x28e89c = 0xDED6A78B I hope it helps..
